Kimdionedaelliviz
Answered

Four times a number increased by 5 is 37.What is the number?

Sagot :

Shinalcantaraviz
Let 'n' be the number
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-four times a number increased by 5 is 37
4n + 5 = 37
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Transpose 5 to the right
4n + 5 = 37
4n = 37 - 5
4n = 32
Divide the whole equation with 4
4n/4 = 32/4
n = 8
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Therefore the number is 8

Jers15viz
let:
x-number

4x+5=37
Subtract 5 to both sides
4x=32
Divide both sides by 4
x=8
Hope this helps =)