Answered

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 65 km/h slower than the other. If the two planes are 3438 km apart after 2 hours, what is the rate of each plane?

Sagot :

2x+2(x-65)=3438
2x+2x-130=3438
4x=3568
x=892
x-65=827

Therefore,
faster plane=x=892 km/h
slower plan=x-65=827 km/h

Check:
2(892)+2(892-65)=3438
1784+2(827)=3438
1784+1654=3438
3438=3438