[tex]Let\ x_{1}=y \\ Let\ x_{2}=y \\ Let\ x_{3}=y \\ \\ Let's\ try\ trial\ and\ error\ or\ basic\ math\ to\ solve\ this\ problem. \\ \\ \frac{3}{5}\times \frac{2}{2}= \boxed{\frac{6}{10}} \\ \frac{3}{5}\times \frac{3}{3}=\boxed{ \frac{9}{15}} \\ \frac{3}{5}\times\frac{4}{4}=\boxed{ \frac{12}{20}} \\ Therefore, \\ \\ \boxed{\boxed{ \frac{6}{10},\frac{9}{15},\frac{12}{20}= \frac{3}{5}}} \\ \\ Hope\ it\ Helps:) \\ Domini [/tex]
