An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.
answer: d = 1720 m
solution: Given:a = +3.2 m/s2t = 32.8 svi = 0 m/s
Find:d = ??d = vi*t + 0.5*a*t2d = (0 m/s)*(32.8 s)+ 0.5*(3.20 m/s2)*(32.8 s)2d = 1720 m