Let 'x' be the speed of Andrew's car
at 8am Jessica passed a church and @12noon was overtaken by Andrew's car
Just before the overtaking happened, Jessica traveled for 4hours
And Andrew traveled for 2 hours(10am-12nn)
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Since both traveled the same distance from church up to some point @12nn then you can equate it as:
35(4hrs) = x(2hours)
x = (35×4) ÷ 2
x = 70kph