Solution:
This system of linear equations in two variables can be solved by using elimination method
3x + 4y = 8 Eq. 1
4x + 5y = 10 Eq. 2
Multiplying Eq. 1 by 5
(3x + 4y = 8) × 5
15x + 20y = 40 Eq. 3
Multiplying Eq. 2 by -4
(4x + 5y = 10) × -4
-16x - 20y = -40 Eq. 4
Adding Eq. 3 and Eq. 4
15x + 20y = 40
+ (-16x - 20y = -40)
-x = 0
Solving for x
x = 0
Solving for y (using Eq. 1)
3(0) + 4y = 8
4y = 8
y = 2
Therefore, x = 0 and y = 2
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