4x2 + 4y2 = 25 whats the answer?​

Sagot :

For X_2:

[tex]x \frac{}{2} = \frac{25}{4} - y \frac{}{2} [/tex]

For Y_2:

[tex]y \frac{}{2} = \frac{25}{4} - x \frac{}{2} [/tex]

Step-by-step explanation:

Solve for X_2:

Subtract 4y2 from both sides.

[tex]4x \frac{}{2} = 25 - 4y \frac{}{2} [/tex]

Divide both sides by 4.

[tex] \frac{4x \frac{}{2} }{4} = \frac{25 - 4y \frac{}{2} }{4} [/tex]

Dividing by 4 undoes the multiplication by 4.

[tex]x \frac{}{2} = \frac{25 - 4y \frac{}{2} }{4} [/tex]

Divide 25 – 4y2 by 4.

[tex]x \frac{}{2} = \frac{25 \frac{}{} }{4} - y \frac{}{2} [/tex]

Solve for Y_2:

Subtract 4x2 from both sides.

[tex]4y \frac{}{2} = 25 - 4x \frac{}{2} [/tex]

Divide both sides by 4.

[tex] \frac{4y \frac{}{2} }{4} = \frac{25 - 4x \frac{}{2} }{4} [/tex]

Dividing by 4 undoes the multiplication by 4.

[tex]y \frac{}{2} = \frac{25 - 4x \frac{}{2} }{4} [/tex]

Divide 25 – 4x2 by 4.

[tex]y \frac{}{2} = \frac{25}{4} - x \frac{}{2} [/tex]

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