Sagot :
Problem:
What is the area of a square whose side is 4x - 1?
Solution:
Area = S²
Area = (4x - 1)²
Area = (4x - 1)(4x - 1)
Area = 16x² - 4x - 4x + 1
Area = 16x² - 8x + 1
Area = S²
Area = (4x - 1)²
Area = (4x - 1)(4x - 1)
Area = 16x² - 4x - 4x + 1
Area = 16x² - 8x + 1