factor then solve x²-5x=24

First, arrage the equation in a standard form (ax² + bx + c = 0). We will gonna do it by transposing all terms from right to left, until all the terms on the right is zero. By transposing, negate the symbol of the term.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: {x}^{2} - 5x = \blue{24} \\ {x}^{2} - 5x \blue{ - 24} = 0[/tex]

[tex] {x}^{2} - 5x - 24 = 0 \\(x + 3)(x - 8) = 0 \\x + 3 = 0 \: \: \: \: \: \: x - 8 = 0 \\ x = - 3 \: \: \: \: \: \: x = 8[/tex]

[tex](x + 3)(x - 8)[/tex]

[tex]x = - 3 \: \: \: \: \: \: x = 8[/tex]

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