Answer:
Step-by-step explanation:
[tex] = \frac{n}{2} (2a1 + (n - 1)d)[/tex]
where,
S is the sum or series
n is the number of terms
a1 is the first term
an is the nth term and,
d is the common difference equals to 2 from 4-2.
[tex] = \frac{10}{2} \: (2(2) + (10 - 1)2)[/tex]
[tex] = 5 \: (4+ (9)2)[/tex]
[tex] = 5 \: (4+ 18)[/tex]
[tex] = 5 \: \times 22[/tex]
[tex] = 110[/tex]
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