Answer:
r = 2
Step-by-step explanation:
[tex] \tt{}a _{n}= a _{1}r {}^{n - 1} [/tex]
[tex] \tt{}8 = \frac{1}{8} r {}^{7 - 1} [/tex]
[tex] \tt{}8 = \frac{1}{8} {r}^{6} [/tex]
[tex] \tt{} \frac{8}{ \frac{1}{8} } = {r}^{6} [/tex]
[tex] \tt{}8 \times \frac{8}{1} = {r}^{6} [/tex]
[tex] \tt{} \frac{64}{1} = r {}^{6} [/tex]
[tex] \tt{}64 = {r}^{6} [/tex]
[tex] \tt{} \sqrt[6]{64} = r[/tex]
[tex] \tt{}2 = r[/tex]
[tex] \boxed{ \huge \boxed{ \tt{}r = 2}} \\ \\ \\ \\ \\ [/tex]
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