Answer:
There are 58 seats in the last row.
Step-by-step explanation:
Given: [tex]a_1=10[/tex], [tex]d=2[/tex], [tex]n=25[/tex]
Find: [tex]a_{25}=?[/tex]
Formula: [tex]a_n=a_1+(n-1)d[/tex]
Solution:
[tex]a_n=a_1+(n-1)d\\a_{25}=10+(25-1)2\\a_{25}=10+(24)2\\a_{25}=10+48\\\boxed{a_{25}=58}[/tex]
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