Sagot :
2/x + 3/(x-2)
= 2(x-2)/(x^2-2x) + 3x/(x^2-2x)
= (2x-4) + 3x / (x^2-2x)
= (5x - 4) / (x^2-2x)
= 2(x-2)/(x^2-2x) + 3x/(x^2-2x)
= (2x-4) + 3x / (x^2-2x)
= (5x - 4) / (x^2-2x)
what is the sum of 2/x+3/x-2
Combine fractions with similar denominators.
[tex] - 2 + \frac{2 + 3}{x} [/tex]
Add 2 and 3
[tex] - 2 + \frac{5}{x} [/tex]
To write – 2 as a fraction with a common denominator,multiply by x/x
[tex] - 2 .\frac{x}{x} + \frac{5}{x} [/tex]
Combine –2 and x/x
[tex] - \frac{2x}{x} + \frac{5}{x} [/tex]
Combine the numerators over the common denominator
[tex] \frac{ - 2x + 5}{x} [/tex]
Factor – 1 out of – (2x) – 1 (–5).
[tex] - \frac{(2x) + 5}{x} [/tex]
Factor −1 out of −(2x)−1(−5).
[tex] - \frac{(2x - 5)}{x} [/tex]
Simplify the expression
Rewrite −(2x−5) as −1(2x−5)
[tex] \frac{ - 1(2x - 5)}{x} [/tex]
Move the negative infront of yhe fraction
[tex] - \frac{ 2x - 5}{x} [/tex]
ANSWER
[tex] - \frac{2 \times - 5}{x} [/tex]
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