Find the 10th term of an arithmetic sequence with
first term 1/7 and the common difference 2/5.
[tex]a_{n} = a_{1} + (n - 1) \: d[/tex]
where:
[tex]a_{1}[/tex] = is the first term.
n = is the nth term.
d = is the common difference.
[tex]a_{n} = a_{1} + (n - 1) \: d \\ \\ a_{10} = \frac{1}{7} + (10 - 1) \: \frac{2}{5} \\ \\ a_{10} = \frac{1}{7} + (9) \: \frac{2}{5} \\ \\ a_{10} = \frac{1}{7} + \frac{18}{5} [/tex]
[tex]a_{10} = \frac{131}{35} [/tex] or [tex]3 \frac{26}{35} [/tex]
The 10th term is [tex] \frac{131}{35} [/tex] or [tex] 3\frac{26}{35} [/tex]
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