Question:
A 0.00300 M solution of an acid is 12% ionized. Calculate the acid ionization constant Ka:
Answer:
Acid is 12
% ionized. So, the degree of dissociation (
α
) is
[tex]a=\frac{12}{100}=0.12[/tex]
Now for the weak acid, the acid dissociation constant (
K
a
) is being approximately given by:
[tex]Ka=Ca^{2}=0.00300 x(0.12)^2=4.32x10^-5[/tex]
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