Tinambacanmarianerosviz
Answered

Quadratic Equation
6.x²=x-12
7.x²=81
8.x²+5x+32=0
9.2x²+3x=5
10.3x²-14x=7

Find the value of b²-4ac and determine the kind of roots the equation will have​

Sagot :

ARMYLviz

DETERMINING THE DISCRIMINANT, NUMBER OF REAL ROOTS AND NATURE OF ROOTS

  • In determining the discriminant, find the values of a, b, c of each equation but make sure that it is in standard form.

GIVEN

x²= x-12

STANDARD FORM

x²-x+12=0

a= 1 b= -1 c= 12

DISCRIMINANT

b²-4ac

(-1)²-4(1)(12)

1-48= -47

NUMBER OF REAL ROOTS

0

NATURE OF ROOTS

Not real

GIVEN

x²= 81

STANDARD FORM

x²-81=0

a= 1 b= 0 c= -81

DISCRIMINANT

b²-4ac

(0)²-4(1)(-81)

0+324= 324

NUMBER OF REAL ROOTS

2

NATURE OF ROOTS

Real Rational Unequal

GIVEN

x²+5x+32=0

a= 1 b= 5 c= 32

DISCRIMINANT

b²-4ac

(5)²-4(1)(32)

25-128= -103

NUMBER OF REAL ROOTS

0

NATURE OF ROOTS

Not real

GIVEN

2x²+3x= 5

STANDARD FORM

2x²+3x-5=0

a= 2 b= 3 c= -5

DISCRIMINANT

b²-4ac

(3)²-4(2)(-5)

9+40= 49

NUMBER OF REAL ROOTS

2

NATURE OF ROOTS

Real Rational Unequal

GIVEN

3x²-14x= 7

STANDARD FORM

3x²-14x-7=0

a= 3 b= -14 c= -7

DISCRIMINANT

b²-4ac

(-14)²-4(3)(-7)

196+84= 280

NUMBER OF REAL ROOTS

2

NATURE OF ROOTS

Real Irrational Unequal

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