Answered

solve the length of a rectangular lot is three times its width . If the length is decreased by 20 feet and the width is increased by 10 feet, the area is increased by 200 feet. find the dimensions

Sagot :

Jers15viz
l=3w

(l-20)(w+10)=A+200
(3w-20)(w+10)=A+200
[tex]3w^{2}+30w-20w-200=A+200[/tex]
[tex]3w^{2}+10w-200=A+200 [/tex]
[tex]3w^{2}+10w-400=3w^{2} [/tex]
10w-400=0
10w=400
w=40

l=3w
l=3(40)
l=120

Therefore the length is 120 and the width is 40