1. [tex] \frac{4}{8} [/tex] × [tex] 2 \frac{5}{6} [/tex]
Make [tex] 2 \frac{5}{6} [/tex] an improper fraction first.
[tex] \frac{17}{6} [/tex]
[tex] \frac{4}{8} [/tex] × [tex] \frac{17}{6} [/tex]
[tex] \frac{68}{48} [/tex]
[tex] 1 \frac{20}{48} [/tex] or [tex] 1 \frac{5}{8} [/tex]
2. 4 × [tex] \frac{4}{6} [/tex]
[tex] \frac{16}{6} [/tex] or [tex] \frac{8}{3} [/tex] or [tex] 2 \frac{2}{3} [/tex]
