[tex]7x-4 \leq 2x + 8 \ \ |\ subtract\ 2x\ to\ both\ sides \\\\7x-2x -4\leq 2x-2x+8 \\\\5x -4\leq 8\ \ | \ add\ 4\ to\ both\ sides \\\\5x-4+4 \leq 8+4\\ \\5x\leq 12\ \ | \ divide \ both \ sides\ by\ 2 \\ \\x\leq \frac{12}{5} \\\\x\leq 2\frac{2}{5} \\\\x \in<2\frac{2}{5},+\infty ) [/tex]
