Let the three consecutive integers be x-1, x, and x+1
(x-1)^2 + x^2 + (x+1)^2 = 110
(x^2 - 2x + 1) + x^2 + (x^2 + 2x + 1) = 110
3x^2 + 2 = 110
3x^2 = 108
x^2 = 36
x = +/- 6
thus the consecutive integers can be:
A: {5, 6, 7}
B: {-7, -6, -5}
Hope this helps :)
