Sagot :
Let 'x' be the 1st number
'x +2' be the 2nd number
'x+4' be the 3rd number
x +( x + 2) + (x + 4) = 126
combine like terms
x + x + x = 126 - 2 - 4
3x = 120
x = 40
x+2 = 40 + 2
= 42
The largest integer is represented by x+4
x + 4 = 40 + 4
= 44
Therefore the numbers are 40,42, and 44. The largest integer is 44.
'x +2' be the 2nd number
'x+4' be the 3rd number
x +( x + 2) + (x + 4) = 126
combine like terms
x + x + x = 126 - 2 - 4
3x = 120
x = 40
x+2 = 40 + 2
= 42
The largest integer is represented by x+4
x + 4 = 40 + 4
= 44
Therefore the numbers are 40,42, and 44. The largest integer is 44.
n+(n+2)+(n+4) = 126
3n = 126 -6
3n = 120
n = 40
n+2 = 42
n+4 = 44 is the largest even integer
3n = 126 -6
3n = 120
n = 40
n+2 = 42
n+4 = 44 is the largest even integer