Answered

answer using completing the square method and give the solution and soultion set:
x^2-7x+12=0

Sagot :

Dominiviz
We have to used the factoring of General Trinomial;

[tex] x^{2} -7x+12=( x-4)( x-3) [/tex]

Now we have to check it by using FOIL Method;

[tex](x)(x)= x^{2} \\ \\ (x)(-3)=-3x \\ \\ (-4)(x)=-4 \\ \\ (-4)(-3)=12[/tex]

Combine like terms;
[tex] x^{2} -3x-4x+12= x^{2} -7x+12 \\ \\ x^{2} -7x+12=(x-4)(x-3)[/tex]
Asdfghjkl123456789viz
[tex] x^{2} - 7x + 12 = 0 [/tex]
[tex] x^{2} - 7x = -12 [/tex]
[tex] x^{2} - 7x + \frac{49}{4} = -12 + \frac{49}{4} [/tex]
[tex] (x - \frac{7}{2})^{2} = \frac{1}{4} [/tex]
[tex] x - \frac{7}{2} =± \frac{1}{2} [/tex]
[tex] x = \frac{1}{2} ± \frac{7}{2} [/tex]
[tex] x = \frac{1}{2} + \frac{7}{2} , \frac{1}{2} - \frac{7}{2} [/tex]
[tex] x = \frac{8}{2} , -\frac{6}{2} [/tex]
x = 4 , 3

*Don't mind the letter 'A'*
Hope it helps!