Sagot :
x+y=10
x+4y
let x in (x+y=10) be 0
x+y=10
0+y=10
y=10
let y in (x+4y) be 10
x+4y
x+4(10)
x+40
x=-40
So in using substitution method and by substituting it by 0 you will get an answer of y=10 and x=-40
x+4y
let x in (x+y=10) be 0
x+y=10
0+y=10
y=10
let y in (x+4y) be 10
x+4y
x+4(10)
x+40
x=-40
So in using substitution method and by substituting it by 0 you will get an answer of y=10 and x=-40
x + y = 10 ----equation 1
x = 4y -----equation 2
substitute equation 2 to equation 1
x + y = 10
4y + y = 10
5y = 10
y = 2
substitute y=2 to equation 2
x = 4y
x =4(2)
x = 8
x = 4y -----equation 2
substitute equation 2 to equation 1
x + y = 10
4y + y = 10
5y = 10
y = 2
substitute y=2 to equation 2
x = 4y
x =4(2)
x = 8