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The 12th term in an arithmetic sequence, where the 1st term is 2 and the common difference is 4, is:

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An = A1 + (n-1)d
where A1 is the first term
             n is the number of terms
             d is the common difference
Given: A1 = 2
             n = 12
             d = 4
A12 = 2 + (12-1)4
A12 = 2 + 11(4)
A12 = 2 + 44
A12 = 46
therefore the 12th term is 46.