i think we will solve for x. so 2(cube root of 1-3x)=-4 we will cube both side so the radical will now cancel 8(1-3x)/8=-64/8 1-3x=-8 so "x=3" then if we substitute the value of x from the given equation we will get -4
2∛1-3x = -4 Divide both side by 2 ∛1-3x = -2 to cancel the radical raise both side by 3 the equation will be, 1-3x= -8 transpose 1 to the right -3x=-9 divide the equation by-3 x=3
