Mariesolcuribaviz
Answered

Find the sum of the first 50 even positive integers

Sagot :

Shinalcantaraviz
using the sum of arithmetic progression you'll have:
[tex]S_n = [2a_1 +(n-1)d] \frac{n}{2} [/tex]
where a1=2
              n=50
              d=2
[tex]S_n = [2(2) + (50-1)(2)] \frac{50}{2}[/tex]
[tex]S_n = [4 + 49(2)](25)[/tex]
[tex]S_n = 2,550[/tex]

Viz Other Questions