taking the area of the first as:
20yrds(40yrds) = 800 sq. yrds
getting John's rate in mowing you'll have:
R = 800sq.yrds/2hours
R = 400yd²/hour
get the area of the second
A = 40yds(80yds)
= 3,200 sq. yds
getting the number of hours needed to mow the area you'll have:
t = 3,200/400
t = 8 hours
then John's estimate is incorrect.