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Solve the following equation by completing the square. 2x^2+ 2y^2-8x+5=0?

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Ljaydgviz
⇒ 2x^2+ 2y^2-8x+5=0 / 2 
= x^2 +y^2 -4x +5/2 = 0
= x^2 +y^2 -4x +10/4 = 5/2 +10/4
= (x+5/2) = 5
= x + 5/2 = (plus and minus) √5
= x = √5 (plus and minus) 5/2