Dudzmargviz
Answered


Alex’s father is
five more than twice as old as he is now.  Six years ago, he was one-third as old.
How old are they now?

Sagot :

let
                present      six years ago          
alex' age       x                 x-6                         
father         5+ 2x            (5+2x) - 6  becomes  2x-1                        

1/3(2x-1) = x-6      since six years ago, alex's age is 1/3 of his father's age
2x-1 =  3x -18      solve for x

x= 17 (alex's age)
5 + 2x = 39 (father's age)