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the length of the rectangle is 6 x^{2} plus 2x plus1 and the width is 2x plus.find the perimeter and the area of the rectangle

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Shinalcantaraviz
For perimeter:
P = 2L + 2W
L = 6x² + 2x + 1
W = 2x + 1
P = 2(6x² + 2x + 1) + 2(2x + 1)
P = 12x² + 4x + 2 + 4x + 2
P = 12x² + 8x + 4
For the area
A = LW
A = (6x² + 2x + 1)(2x + 1)
A = 12x³ + 6x² + 4x² + 2x + 2x + 1
A = 12x³ + 10x² + 4x + 1