Rubymatira0912bheviz
Answered

Solve for the missing parts of right triangle ACB  a=75.2 cm , c= 148.5 cm

Sagot :

[tex]b= \sqrt{148.5^{2} - 75.2^{2} } [/tex]
b = 128.05 cm
[tex]A = sin^{-1} \frac{75.2}{148.5} [/tex]
A = 30.42°
[tex]B= sin^{-1} \frac{128.05}{148.5} [/tex]
B = 59.57°