Answered

How many moles are in 98.3 grams of Al(OH)³

Sagot :

Mizuviz
Use formula
[tex]n= \frac{m}{MM} [/tex]
where n = moles
m = mass
MM = molar mass

Solve
[tex]n= \frac{98.3 \: g}{78.01 \: g/mol} \\ n=1.26 \: mol[/tex]

∴ There are 1.26 mol.