Dennisdauloviz
Answered

([tex](28m^5x^5-44m^6x^6-12m^4x^3)/(4m^3y^2) [/tex]

Sagot :

Riza1viz
[tex]\frac{ 28m^5x^5-44m^6x^6-12m^4x^3}{4m^3y^2 } = \frac{4m^3( 7m^2x^2-11m^3x^6-3m x^3)}{4m^3y^2 } = \frac{ 7m^2x^5-11m^3x^6-3m x^3 }{ y^2 } \\\\ m\neq 0 \ \ \ and \ \ \ y\neq 0[/tex]