domain are the values given for x and range for y
to find the range, all you have to do is substitute the given domain in the function
f(x) = 4/3x + 1
f(3) = (4/3)(3) + 1
f(3) = 4 + 1
f(3) = 5
f(6) = (4/3)(6) + 1
f(6) = 9 + 1
f(6) = 10
f(9) = (4/3)(9) + 1
f(9) = 12 + 1
f(9) = 13
f(12) = (4/3)(12) + 1
f(12) = 16 + 1
f(12) = 17
Range is { 5, 10, 13, 17 }
