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What is the standard form of this quadratic equation (x + 14) (x – 14) = 0 ? Help me please.

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XyLynviz
 ax²+b+c=0
ax (exponent of 2) plus b plus c equals zero
x²-x-196=0
x²-x-196=(x-14)(x+14)

setting each linear factor to zero, we get:
x-14=0          x+14=0
x=14              x= -14
[tex] x^{2} [/tex]-14x+14x-196=0