[tex]r = \frac{st}{u} k[/tex]
[tex] \frac{3}{8} = \frac{10(3)}{56} k[/tex]
[tex]k = \frac{7}{10} [/tex]
with given s = 6, t = 7 and u = 84 you'll have r as:
[tex]r = \frac{st}{u} k[/tex]
[tex]r = \frac{6(7)}{84} ( \frac{7}{10}) [/tex]
[tex]r = \frac{7}{20} [/tex]