Use the first statement to solve for the
constant k, 42 horses for 21 days can be fed with 270 kg of corn, then,
(Number of Horses)(Number of Days)k=Kilogram of
Corn
[tex](42)(21)k=270[/tex]
[tex]882k=270[/tex]
[tex]k= \frac{270}{882} = \frac{15}{49} [/tex]
With k = 15/49, use the value for k in solving the number of
days that 360 kg of corn would feed 21 horses. given the second statement.
[tex](21)(n)( \frac{15}{49}) =360[/tex]
[tex]n= \frac{(360)(49)}{(21)(15)} = \frac{17640}{315} =56[/tex]
n=56
Hence, 360 kg of corn would feed 21 horses in
56 days.
