Since this involves combination where there are 2003 people and 2000 people to be selected then we'll have it done using the combination formula taken to be as:
[tex]C = S = \frac{P}{r!} [/tex]
[tex] _{2003} C _{2000} = \frac{2003(2002)(2001)(2000)...(4)}{2000!} [/tex]
[tex] _{2003} C _{2000} = 1,337,337,001[/tex] combinations
