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can you show me how to solve this set of linear equation: x+y-z=1, -y+z=0, x+8y-z=28

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Cheahjimmyviz
- y+z =0  then    y = z
   x+y-z = 1      then        x = 1

x+8y-z = 28
1+ 8y-y =28          / since y = z
1+7y = 28
   y =  27/7
the answer is     
                            x = 1,    y = 27/7,    &   z = 27/7