Shashallyviz
Answered

What is p(x)=x^3+3x^2+3x+1
x= -1
REMAINING ZEROS OF THE POLYNOMIAL FUNCTION.

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Cheahjimmyviz
p(x)= x³ + 3x²+3x + 1
x= -1  then    x+1  is a factor of P(x)
to get the other factors divide
  (x³+3x²+3x+1)/x+1
= x²+2x+1 =  (x+1)(x+1)
so
(x+1)(x+1)(x+1) = 0
the other two zeros are also  -1