since we're up to the components x and y of the force,
say the angle that we're dealing with as along x-axis
then we'll have the components:
for [tex]31^{0} 20'[/tex] (angle made with the x-axis)
Horizontal Component
Fx = 786 (cos [tex]31^{0} 20'[/tex])
= 671.367 lbs
Vertical Component
Fy = 786 (sin [tex]31^{0} 20'[/tex])
= 408.733 lbs.
for [tex]58^{0} 40'[/tex] (angle made with the x-axis)
Horizontal Component
Fx = 786 (cos [tex]58^{0} 40'[/tex])
= 408.733 lbs
Vertical Component
Fy = 786 (sin [tex]58^{0} 40'[/tex])
= 671.367 lbs
REMEMBER that the angles i'm using is the angle that makes with the x-axis
