how to find the y intercept of the line through the point (2,3) and (1,4)










Sagot :

by using the formula ...
y-y1 = (y2-y1/x2-x1) (x-x1)
substitute the given points ..
y-3 = (4-3/1-2) (x-2)
y-3 = -1 (x-2)
y-3 = -x+2
y = -x + 5
y-intercept = 5
[tex](2,3) \ and \ (1,4) \\ \\ First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{4-3}{1-2} = \frac{1}{-1} =-1\\\\the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\3=-1\cdot 2+b \\ \\3=-2+b \\ \\ b=3+2\\\\b=5 \\ \\ y=-x+5 \\ \\ Answer: \ y - intercept = 5[/tex]