AliceHviz
AliceHviz
Math
Answered
What is (2a^2b-4a^2B^3)/(6a^3b^3) and how?
Sagot :
Riza1viz
Riza1viz
[tex]\frac{ 2a^2b-4a^2b^3 }{6a^3b^3 } =\frac{2a^2b (1-2 b^2) }{6a^3b^3 } =\frac{ 1-2 b^2 }{3a b^2 }[/tex]
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