[tex]\frac{-3x-2}{x^2-2x-3} + \frac{2}{x+1 }=\frac{-3x-2}{(x+1 )(x-3)} + \frac{2}{x+1 }=\frac{-3x-2+2(x-3)}{(x+1 )(x-3)} =\\\\=\frac{-3x-2+2 x-6}{(x+1 )(x-3)}=\frac{- x-8}{(x+1 )(x-3)} =-\frac{x+8}{(x+1 )(x-3)} \\\\\\(x+1)(x-3)\neq 0 \\ x+1\neq 0 \ \ and\ \ x+3 \neq 0 \\x \neq -1 \ \ and\ \ x \neq -3\\D=R\setminus \left \{ -1,3 \right \}[/tex]
