Why is this in Chemistry?
Anyway.
In order to solve system of equations using substitution, remember these two steps:
1. Isolate a variable that you think will have a simplified equation.
2. Plug-in this variable on the next equation.
Let's make the first system as an example.
On the first equation, let us isolate x on the left hand side.
[tex]2x+2y=2 \\\\
2x=2-2y\\\\
x=1-y
[/tex]
Now that we have a value for x, we substitute that on the second equation.
[tex]2(1-y)+3y=-2\\\\
2-2y+3y=-2\\\\
y=-2-2=-4[/tex]
Plugging that value of y on the first equation, we get:
[tex]2x+2(-4)=2\\\\
2x-8=2\\\\
2x=10\\\\
x=5[/tex]
Do the same with the second problem. Hope that helps.
If you're having problems dealing with the second problem, don't hesitate to message me. :)
