Answered

factor out t2
– 0.3t – 0.10

Sagot :

Riza1viz
[tex]t^2- \frac{3}{10}t - \frac{10}{100}= t^2- \frac{3}{10}t - \frac{1 }{10 }=\frac{10t^2}{10}- \frac{3t}{10} - \frac{1 }{10 } =\frac{10t^2-3t -1}{10}= \\\\=\frac{10t^2-5t+2t-1}{10}=\frac{5t(2t-1)+(2t-1)}{10}= \frac{ (2t-1) (5t+1)}{10}[/tex]