Sagot :
1) Find the acceleration:
Equation: a= (v2²-v1²) / 2d
where:
a=acceleration
v2=final velocity ( 0 m/s)
v1=initial velocity (40 m/s)
d=distance (120 m)
Solution:
a=(v2²-v1²) / 2d
a=(0²-40²) / 2(120)
a= -1600 / 240
a= -20/3
a= -6.67 m/s²------->answer
2) Find time:
t=v2-v1/ a
t= 0-40 / -6.67
t= -40/-6.67
t = 6 seconds--------->answer
Equation: a= (v2²-v1²) / 2d
where:
a=acceleration
v2=final velocity ( 0 m/s)
v1=initial velocity (40 m/s)
d=distance (120 m)
Solution:
a=(v2²-v1²) / 2d
a=(0²-40²) / 2(120)
a= -1600 / 240
a= -20/3
a= -6.67 m/s²------->answer
2) Find time:
t=v2-v1/ a
t= 0-40 / -6.67
t= -40/-6.67
t = 6 seconds--------->answer