Sagot :
[tex]Area : \ A = 16 \ cm^2 \\ the \ side \ the \ square : \ a=? \\ \\A= a^2 \\ \\a^2=16 \\ a=\sqrt{16}\\ a=4 \ cm \\\\Answer: \ The \ side \ the \ square \ is \ 4 \ cm[/tex]
RECALL THAT A = S^2, SO DO IT IN REVERSE. FIND THE SQUARE ROOT OF 16, AND THE ANSWER IS 4 CM.