52998viz
52998viz
Math
Answered
12x^4-25x^3+18x^2+7x-20/3x-4
Sagot :
Riza1viz
Riza1viz
[tex]\frac{12x^4-25x^3+18x^2+7x-20}{3x-4}=\\\\=\frac{12x^4 -16x^3-9x^3 +12x^2 +6x^2 -8x+15x-20}{3x-4}=\\\\=\frac{4x^3(3x -4)-3x^2(3x -4)+2x(3x -4)+5(3x-4)}{3x-4}=\\\\=\frac{ (3x -4)(4x^3-3x^2+2x+5) }{3x-4}\\\\= 4x^3-3x^2+2x+5[/tex]
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