Theresajamaicaviz
Answered

f(x)=((x^2+1)^1/2(x^3-3)^1/4)/(x^4+5)^1/3
answer niyo po. Calculus.

Sagot :

Rhyckayenviz
The answer is = {(x^4+5)^1/3 * (x^3-3)^1/4 * (x^2+1)^1/2 * x [(3x/4) (x^3-3)^-1 + 2 (x^2+1)-1 *(4x^2/3) * (x^4+5)^-1]}/ (x^4 +5)^2/3.... Hope you've understood... I also included the solution sorry for the bad handwriting :-)
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